If \( z \) is a complex number then the equation \( z^{2}+z|z|+|z|^... VIDEO
If \( z \) is a complex number then the equation \( z^{2}+z|z|+|z|^{2}=0 \) is satisfied by ( \( \omega \) and \( \omega^{2} \) are imaginary cube roots of unity)
\( \mathrm{P} \)
(A) \( z=k \theta \) where \( k \in R \)
(B) \( z=k \omega^{2} \) where \( k \) is non negative real
(C) \( \mathrm{z}=\mathrm{k} \omega \) where \( \mathrm{k} \) is positive real
(D) \( z=k \omega^{2} \) where \( k \in R \).
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