Duration: 0:00

16 views

0

Prove that the equation to the circle, which passes through the focus and touches the parabola \( y^{2}=4 a x \)
\( \mathrm{P} \) at the point \( \left(a t^{2}, 2 a t\right) \), is \( x^{2}+y^{2}-a x\left(3 t^{2}+1\right)-a y\left(3 t-t^{3}\right)+3 a^{2} t^{2}=0 \).

W Prove also that the locus of its centre is the curve \( 27 a y^{2}=(2 x-a)(x-5 a)^{2} \).
📲 PW App Link - https://bit.ly/YTAI_PWAP
🌐 PW Website - https://www.pw.live/