A body is projected vertically up at \( \mathrm{t}=0 \) with \( a \) velocity of \( 98 \mathrm{~...

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A body is projected vertically up at \( \mathrm{t}=0 \) with \( a \) velocity of \( 98 \mathrm{~m} / \mathrm{s} \). Another body is projected from the same point with same velocity after 4 seconds. Both bodies will meet at \( \mathrm{t}= \)
(1) \( 6 \mathrm{~s} \)
(2) \( 8 \mathrm{~s} \)
(3) \( 10 \mathrm{~s} \)
(4) \( 12 \mathrm{~s} \)
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