Duration: 5:30

0 views

0

A particle is projected from level ground. Assuming projection point as origin. \( x \)-axis along horizontal and \( y \)-axis along vertically upwards. If particle moves in \( x-y \) plane and its path is given by \( y=a x-b x^{2} \) where \( a \), \( b \) are positive constants. Then match the physical quantities given in column-1 with the values given in column-II. ( \( g \) in column II is acceleration due to gravity.)
\begin{tabular}{|l|l|l|l|}
\hline \multicolumn{2}{|c|}{ Column I } & \multicolumn{2}{c|}{ Column II } \\
\hline (A) & \begin{tabular}{l}
Horizontal component of \\
velocity
\end{tabular} & (P) & \( \frac{a}{b} \) \\
\hline (B) & Time of flight & (Q) & \( \frac{a^{2}}{4 b} \) \\
\hline (C) & Maximum height & (R) & \( \sqrt{\frac{g}{2 b}} \) \\
\hline (D) & Horizontal range & (S) & \( \sqrt{\frac{2 a^{2}}{b g}} \) \\
\hline
\end{tabular}
\begin{tabular}{lllll}
& A & B & C & D \\
(1) & R & S & Q & P \\
(2) & R & S & P & Q \\
(3) & S & P & Q & S \\
(4) & R & P & S & Q
\end{tabular}
W.


📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live