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Ceaser Cipher Text Project in Python | Urdu/Hindi

Note : Recplace (greater than) and (less than) with their sign/symbol ( Because Youtube donot allow angle brackets in description ) OR You can get this code on github by using github link

Code github Link : https://github.com/ubaidahmadceh/python_projects/blob/main/Ceaser_Cipher_Text.py

code :

alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

user_choice = input("Type 'encode' to encrypt, type 'decode' to decrypt:\n")
text = input("Type your message:\n").lower()
shift = int(input("Type the shift number:\n"))

def encrypt(text, shift):
encoded_text = ""
for letter in text:
position = alphabet.index(letter)
new_position = position + shift
new_letter = alphabet[new_position]
encoded_text += new_letter
print(f"The encoded text is {encoded_text}")

def decrypt(text, shift):
original_text = ""
for letter in text:
position = alphabet.index(letter)
new_position = position - shift
new_letter = alphabet[new_position]
original_text += new_letter
print(f"The encoded text is {original_text}")

if user_choice == "encode":
encrypt(text, shift)
elif user_choice == "decode":
decrypt(text, shift)
else:
print("Wrong entry")














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