From a circular disc of radius \( \mathrm{R} \), a square is cut ou...

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From a circular disc of radius \( \mathrm{R} \), a square is cut out with a radius as its diagonal. The center of mass of remainder part is at a distance (from the centre):-
\( \mathrm{P} \)
W
(1) \( \frac{R}{(4 \pi-2)} \)
(2) \( \frac{R}{2 \pi} \)
(3) \( \frac{\mathrm{R}}{(\pi-2)} \)
(4) \( \frac{\mathrm{R}}{(2 \pi-2)} \)
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