Given the following data : \( \begin{array}{lll}\text { Substance } & \Delta \mathbf{H}_{\mathrm...

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Given the following data :
\( \begin{array}{lll}\text { Substance } & \Delta \mathbf{H}_{\mathrm{f}}(\mathbf{k J} / \mathrm{mol}) & \mathbf{S}(\mathbf{J} / \mathrm{mol} \mathrm{K}) \\ \mathrm{FeO}(\mathrm{s}) & -266.3 & 57.49 \\ \mathrm{C}(\text { Graphite }) & 0 & 5.74 \\ \mathrm{Fe}(\mathrm{s}) & 0 & 27.28 \\ \mathrm{CO}(\mathrm{g}) & -110.5 & 197.6\end{array} \)
Determine at what temperature the following reaction is spontaneous?
\[
\mathrm{FeO}(\mathrm{s})+\mathrm{C} \text { (graphite) } \longrightarrow \mathrm{Fe}(\mathrm{s})+\mathrm{CO}(\mathrm{g})
\]
(A) \( 298 \mathrm{~K} \)
(B) \( 668 \mathrm{~K} \)
(C) \( 966 \mathrm{~K} \)
(D) \( \Delta \mathrm{G} \) is +ve, hence the reaction will never be spontaneous
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