Helium can be excited to the \( 1 s^{1} 2 p^{1} \) configuration by light of \( 58.44 \mathrm{~n...

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Helium can be excited to the \( 1 s^{1} 2 p^{1} \) configuration by light of \( 58.44 \mathrm{~nm} \). The lowest excited singlet state, with the configuration \( 1 s^{1}, 2 s^{1} \) lies \( 4857 \mathrm{~cm}^{-1} \) below the \( 1 s^{1} 2 p^{1} \) state. What would the average \( \mathrm{He}-\mathrm{H} \) bond energy have to be in order that \( \mathrm{HeH}_{2} \) could form non-endothermically from He and \( \mathrm{H}_{2} \) ? Assume that the compound would form from the lowest excited singlet state of helium. Neglect any differences between \( \Delta U \) and \( \Delta H \). Take \( \Delta H_{f}(\mathrm{H})=2180 \mathrm{~kJ} / \mathrm{mol} \)
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