If \( a^{1 / 3}+b^{1 / 3}+c^{1 / 3}=0 \), prove that \( (a+b+c)^{3}=27 a b c \)
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0If \( a^{1 / 3}+b^{1 / 3}+c^{1 / 3}=0 \), prove that \( (a+b+c)^{3}=27 a b c \)
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