If \( \frac{1-i x}{1+i x}=a-i b \) and \( a^{2}+b^{2}=1 \), where \( a, b \in R \) and \( i=\sqr... VIDEO
If \( \frac{1-i x}{1+i x}=a-i b \) and \( a^{2}+b^{2}=1 \), where \( a, b \in R \) and \( i=\sqrt{-1} \), then \( x \) is equal to
(a) \( \frac{2 a}{(1+a)^{2}+b^{2}} \)
(b) \( \frac{2 b}{(1+a)^{2}+b^{2}} \)
(c) \( \frac{2 a}{(1+b)^{2}+a^{2}} \)
(d) \( \frac{2 b}{(1+b)^{2}+a^{2}} \)
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