If \( f(x)=|(x-1)(x-2)|+\cos |x| \) then the number of values of ' \( x \) ' where \( f(x) \) is....

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If \( f(x)=|(x-1)(x-2)|+\cos |x| \) then the number of
\( \mathrm{P} \)
values of ' \( x \) ' where \( f(x) \) is not differentiable is (are)
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