If the tangent to the ellipse \( x^{2}+4 y^{2}=16 \) at the point \... VIDEO
If the tangent to the ellipse \( x^{2}+4 y^{2}=16 \) at the point \( P(\theta) \) is a normal to circle \( x^{2}+y^{2}-8 x-4 y=0 \) then \( \theta \) equals:
\( \mathrm{P} \)
(a) \( \frac{\pi}{2} \)
(b) \( \frac{\pi}{4} \)
W
(c) 0
(d) \( -\frac{\pi}{4} \)
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