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If the velocity of a particle is \( v=A t+B t^{2} \), where \( A \) and \( B \)
\( \mathrm{P} \) are constants, then the distance travelled by it between \( 1 \mathrm{~s} \) and \( 2 s \) is
[NEET (Phase-I) 2016]
(a) \( \frac{3}{2} A+4 B \)
(b) \( 3 A+7 B \)
(c) \( \frac{3}{2} A+\frac{7}{3} B \)
(d) \( \frac{A}{2}+\frac{B}{3} \)
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