If \( |z+\bar{z}|+|z-\bar{z}|=2 \), then \( z \) lies on (A) a straight line (B) a circle (C) a ...
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If \( |z+\bar{z}|+|z-\bar{z}|=2 \), then \( z \) lies on
(A) a straight line
(B) a circle
(C) a square
(D) None of these
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