In a series \( \mathrm{CR} \) circuit shown in figure, the applied \( \mathrm{P} \) voltage is \...
Channel:
Subscribers:
451,000
Published on ● Video Link: https://www.youtube.com/watch?v=Oc40asMMOUw
In a series \( \mathrm{CR} \) circuit shown in figure, the applied
\( \mathrm{P} \) voltage is \( 10 \mathrm{~V} \) and the voltage across capacitor is
W found to be \( 8 \mathrm{~V} \). Then the voltage across \( \mathrm{R} \), and the phase difference between current and the applied voltage will be respectively be
(1) \( 6 \mathrm{~V}, \tan ^{-1}\left(\frac{4}{3}\right) \)
(2) \( 3 \mathrm{~V}, \tan ^{-1}\left(\frac{3}{4}\right) \)
(3) \( 6 \mathrm{~V}, \tan ^{-1}\left(\frac{5}{3}\right) \)
(4) zero
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live