Let \( a_{1}, a_{2}, a_{3}, \ldots, a_{11} \) be real numbers satisfying \( \mathrm{a}_{1}= \)
\...
Let \( a_{1}, a_{2}, a_{3}, \ldots, a_{11} \) be real numbers satisfying \( \mathrm{a}_{1}= \)
\( \mathrm{P} \)
15, \( 27-2 a_{2}0 \quad \) and
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\( a_{k}=2 a_{k-1}-a_{k-2} \forall k=3,4, \ldots \ldots, 11 \). If \( \frac{a_{1}^{2}+a_{2}^{2}+\ldots \ldots \ldots+a_{11}^{2}}{11}=90 \), then the value of \( \frac{a_{1}+a_{2}+\ldots . .+a_{11}}{11} \) is equal to
(1) 0
(2) 1
(3) 2
(4) 3
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