Solution of inequality \( \frac{-1}{|x|-2} \geq 1 \),
\( P \)
where \( x \in R, x \neq \pm 2 \),.... VIDEO
Solution of inequality \( \frac{-1}{|x|-2} \geq 1 \),
\( P \)
where \( x \in R, x \neq \pm 2 \), is equal to
(1) \( (-2,-1] \cup[1,2) \)
(2) \( (-2,1] \)
(3) \( (1,2] \)
(4) \( x \in R \)
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