The equation \( 2 \sin ^{3} \theta+(2 \lambda-3) \sin ^{2} \theta-(3 \lambda+2) \sin \theta-2 \l...
The equation \( 2 \sin ^{3} \theta+(2 \lambda-3) \sin ^{2} \theta-(3 \lambda+2) \sin \theta-2 \lambda \) \( =0 \) has exactly three roots in \( (0,2 \pi) \), then \( \lambda \) can be equal to
(a) 0
(b) \( 1 / 2 \)
(c) 1
(d) -1
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