The mean of squares of first \( (\mathrm{n}-1) \) natural numbers is:
a. \( \frac{\mathrm{n}^{2}... VIDEO
The mean of squares of first \( (\mathrm{n}-1) \) natural numbers is:
a. \( \frac{\mathrm{n}^{2}}{3}-\frac{\mathrm{n}}{6} \)
b. \( \frac{\mathrm{n}^{2}(\mathrm{n}+1)^{2}}{4} \)
c. \( \frac{n^{2}}{3}+\frac{n}{6} \)
d. \( \frac{n(2 n-1)}{6} \)
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