The number of atoms present in \( 0.05 \mathrm{~g} \) of water is....

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Question The number of atoms present in \( 0.05 \mathrm{~g} \) of water is
(A) \( 1.67 \times 10^{23} \)
(B) \( 1.67 \times 10^{22} \)
(C) \( 5.02 \times 10^{21} \)
(D) \( 1.67 \times 10^{21} \)📲PW App Link - https://bit.ly/YTAI_PWAP 🌐PW Website - https://www.pw.live



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