A \( 100 \mathrm{pF} \) capacitor is charged to a potential difference of \( 80.0 \mathrm{~V} \)...
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A \( 100 \mathrm{pF} \) capacitor is charged to a potential difference of \( 80.0 \mathrm{~V} \), and the charging battery is disconnected. The capacitor is then connected in parallel with a second (initially uncharged) capacitor. If the potential difference across the first capacitor drops to \( 35.0 \mathrm{~V} \), what is the capacitance of this second capacitor?
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