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A boy of mass \( m \) climbs up a conveyor belt with a constant acceleration. The speed of the belt is \( v=\sqrt{g h / 6} \) and the coefficient of friction between the boy and conveyor belt is \( \mu=\frac{5}{3 \sqrt{3}} \). The boy starts from
\( A \) and moves with the maximum possible acceleration till he reaches the highest point \( B \).
The time taken by the boy to reach the height \( h \) is
(1) \( \sqrt{\frac{2 h}{g}} \)
(2) \( \sqrt{\frac{6 h}{g}} \)
(3) \( 2 \sqrt{\frac{h}{g}} \)
(4) None of above
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