A chemist opened a cupboard to find four bottles containing water solutions, each of which has lost its label. Bottles 1, 2, 3 contained colourless solutions, whilst Bottle 4 contained a blue solution. The labels
\( P \) from the bottles were lying scattered on the floor of the cupboard. They were
Copper (II) sulphate
W.
Sodium carbonate
Lead nitrate
hydrochloric acid
- By mixing samples of the contents of the bottles, in pairs, the chemist made the following observations :
\begin{tabular}{cll}
\hline (i) & Bottle \( 1+ \) Bottle 2 & white precipitate \\
\( - \)-(ii) & Bottle \( 1+ \) Bottle 3 & white precipitate \\
(iii) & Bottle \( 1+ \) Bottle 4 & white precipitate \\
(iv) & Bottle \( 2+ \) Bottle 3 & colourless gas evolved \\
\( - \) (v) & Bottle \( 2+ \) Bottle 4 & no visible reaction \\
(vi) & Bottle \( 3+ \) Bottle 4 & blue precipitate
\end{tabular}
Chemical formula of white precipitate in observation (i) is :
- (A) \( \mathrm{CuCl}_{2} \)
(B) \( \mathrm{PbCl}_{2} \)
(C) \( \mathrm{PbCO}_{3} \)
(D) \( \mathrm{CuSO}_{3} \)
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