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A chemist opened a cupboard to find four bottles containing water solutions, each of which has lost its label. Bottles 1, 2, 3 contained colourless solutions, whilst Bottle 4 contained a blue solution. The labels
\( P \) from the bottles were lying scattered on the floor of the cupboard. They were
Copper (II) sulphate
W
Sodium carbonate
Lead nitrate
hydrochloric acid
- By mixing samples of the contents of the bottles, in pairs, the chemist made the following observations :
\( \begin{array}{cll}\text { (i) } & \text { Bottle } 1+\text { Bottle } 2 & \text { white precipitate } \\ -\text { (ii) } & \text { Bottle } 1+\text { Bottle } 3 & \text { white precipitate } \\ \text { (iii) } & \text { Bottle } 1+\text { Bottle } 4 & \text { white precipitate } \\ \text { (iv) } & \text { Bottle } 2+\text { Bottle } 3 & \text { colourless gas evolved } \\ -\text { (v) } & \text { Bottle } 2+\text { Bottle } 4 & \text { no visible reaction } \\ \text { (vi) } & \text { Bottle } 3+\text { Bottle } 4 & \text { blue precipitate }\end{array} \)
Colourless solution present in Bottle-1 is -
(A) \( \mathrm{CuSO}_{4} \)
(B) \( \mathrm{HCl} \)
(C) \( \mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2} \)
(D) \( \mathrm{Na}_{2} \mathrm{CO}_{3} \)
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