A current of \( 2.6 \) ampere is passed through \( \mathrm{CuSO}_{4} \) solution for math x...

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A current of \( 2.6 \) ampere is passed through \( \mathrm{CuSO}_{4} \) solution for math xmlns=http://www.w3.org/1998/Math/MathMLmn6/mn/math minute math xmlns=http://www.w3.org/1998/Math/MathMLmn20/mn/math seconds. The amount of \( \mathrm{Cu} \) deposited is
(At wt. of \( \mathrm{Cu}=63.5 \), Faraday \( =96500 \mathrm{~C} \))
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