A dice is weighted so that the probability of different faces to tu...
A dice is weighted so that the probability of different faces to turn up is as given
\( \mathrm{P} \)
\begin{tabular}{|c|c|c|c|c|c|c|}
\hline Number & 1 & 2 & 3 & 4 & 5 & 6 \\
\hline Probability & \( 0.2 \) & \( 0.1 \) & \( 0.1 \) & \( 0.3 \) & \( 0.1 \) & \( 0.2 \) \\
\hline
\end{tabular}
W
If \( P(A / B)=p_{1} \) and \( P(B / C)=p_{2} \) and \( P(C / A)=p_{3} \) then the values of \( p_{1}, p_{2}, p_{3} \) respectively are .
- Take the events \( A, B \& C \) as \( A=\{1,2,3\}, B=\{2,3,5\} \) and \( C=\{2,4,6\} \)
(A) \( \frac{2}{3}, \frac{1}{3}, \frac{1}{4} \)
(B) \( \frac{1}{3}, \frac{1}{3}, \frac{1}{6} \)
(C) \( \frac{1}{4}, \frac{1}{3}, \frac{1}{6} \)
(D) \( \frac{2}{3}, \frac{1}{6}, \frac{1}{4} \)
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