A force \( F \) pushes a block weighing \( 10 \mathrm{~kg} \) again...
Channel:
Subscribers:
447,000
Published on ● Video Link: https://www.youtube.com/watch?v=EWaToDWRGTg
A force \( F \) pushes a block weighing \( 10 \mathrm{~kg} \) against a vertical wall as shown in the figure.
\( \mathrm{P} \)
The coefficient of friction between the block
W and wall is \( 0.5 \). The minimum value of \( \mathrm{F} \) to start
the upward motion of block is \( \left[\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right] \)
(1) \( 100 \mathrm{~N} \)
(2) \( 500 \mathrm{~N} \)
(3) \( \frac{500}{3} \mathrm{~N} \)
(4) can't be determined
π²PW App Link - https://bit.ly/YTAI_PWAP
πPW Website - https://www.pw.live
Other Videos By PW Solutions
Tags:
pw