A particle is moving along a circular path with a constant speed of \( 10 \mathrm{~ms}^{-1} \). ...
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A particle is moving along a circular path with a constant speed of \( 10 \mathrm{~ms}^{-1} \). What is the magnitude of the change is velocity of the particle, when it moves through an angle of \( 60^{\circ} \) around the center of the circle
[JEE (Main) 2019]
(a) Zero
(b) \( 10 \mathrm{~m} / \mathrm{s} \)
(c) \( 10 \sqrt{2} \mathrm{~m} / \mathrm{s} \)
(d) \( 10 \sqrt{3} \mathrm{~m} / \mathrm{s} \)
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