Duration: 4:05

7 views

0

A particle starting from rest, moves in a circle of radius ' \( r \) '. It attains a velocity of \( V_{0} \mathrm{~m} / \mathrm{s} \) in the \( \mathrm{n}^{\mathrm{t}} \) round. Its angular acceleration will be :-
(1) \( \frac{V_{0}}{\mathrm{n}} \mathrm{rad} / \mathrm{s}^{2} \)
(2) \( \frac{\mathrm{V}_{0}^{2}}{2 \pi n r^{2}} \mathrm{rad} / \mathrm{s}^{2} \)
(3) \( \frac{\mathrm{V}_{0}^{2}}{4 \pi n r^{2}} \mathrm{rad} / \mathrm{s}^{2} \)
(4) \( \frac{\mathrm{V}_{0}^{2}}{4 \pi n r} \mathrm{rad} / \mathrm{s}^{2} \)
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live