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A projectile moves from the ground such that its horizontal displacement is \( x=K t \) and vertical displacement is \( y=K t(1-\alpha t) \), where \( K \) and \( \alpha \) are constants and \( t \) is time.
Find out total time of flight (T) and maximum height attained \( \left(\mathrm{Y}_{\max }\right) \) its
[MP PET 2008]
(a) \( T=\alpha, Y_{\max }=\frac{K}{2 \alpha} \)
(b) \( T=\frac{1}{\alpha}, Y_{\max }=\frac{2 K}{\alpha} \)
(c) \( T=\frac{1}{\alpha}, Y_{\max }=\frac{K}{6 \alpha} \)
(d) \( T=\frac{1}{\alpha}, Y_{\max }=\frac{K}{4 \alpha} \)
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