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A random variable \( \mathrm{X} \) has the following probability
\( \mathrm{P} \) distribution:

W
\begin{tabular}{|c|c|c|c|c|c|}
\hline \( \mathrm{X}: \) & 1 & 2 & 3 & 4 & 5 \\
\hline \( \mathrm{P}(\mathrm{X}): \) & \( k^{2} \) & \( 2 k \) & \( k \) & \( 2 k \) & \( 5 k^{2} \) \\
\hline
\end{tabular}
Then \( \mathrm{P}(\mathrm{X}2) \) is equal to
(1) \( \frac{1}{6} \)
(2) \( \frac{7}{12} \)
(3) \( \frac{1}{36} \)
(4) \( \frac{23}{36} \)
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