A slab of conductivity \( k \) is in the shape of trapezoid as shown in figure. If the two end f...

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A slab of conductivity \( k \) is in the shape of trapezoid as shown in figure. If the two end faces be maintained at temperature \( T_{1}=50^{\circ} \mathrm{C} \) and \( T_{2}=25^{\circ} \mathrm{C} \), then determine the thermal current through the slab by ignoring any heat loss through the lateral surfaces is \( \frac{x k}{\ln (8 / 5)} \mathrm{J} / \mathrm{s} \) ten \( x \) is
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