A solid sphere of radius \( R \) has moment of inertia \( I \) about its geometrical axis. It is...
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A solid sphere of radius \( R \) has moment of inertia \( I \) about its geometrical axis. It is melted into a disc of radius \( r \) and thickness \( t \). If its moment of inertia about the tangential axis (which is perpendicular to plane of the disc), is also equal to \( I \), then the value of \( r \) is equal to
(a) \( \frac{2}{\sqrt{15}} R \)
(b) \( \frac{2}{\sqrt{5}} R \)
(c) \( \frac{3}{\sqrt{15}} R \)
(d) \( \frac{\sqrt{3}}{\sqrt{15}} R \)
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