A spaceship orbits around a planet at a height of \( 20 \mathrm{~km} \) from its surface. Assumi...

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A spaceship orbits around a planet at a height of \( 20 \mathrm{~km} \) from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours around the planet (Given : mass of planet \( =8 \times 10^{22} \mathrm{~kg} \), Radius of the planet \( =2 \times 10^{6} \mathrm{~m} \), Gravitational constant \( G=6.67 \times 10^{-11} \mathrm{Nm}^{2} / \mathrm{kg}^{2} \) ) [JEE (Main) 2019]
(a) 9
(b) 13
(c) 11
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