A stone is projected from ground level with speed \( u \) and at an...
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A stone is projected from ground level with speed \( u \) and at an angle \( \theta \) with horizontal. Some how the
\( \mathrm{P} \) acceleration due to gravity \( (g) \) becomes double
W (that is \( 2 g \) ) immediately after the stone reaches the maximum height and remains same thereafter. Assuming direction of acceleration due to gravity to be vertically downwards, the horizontal range of the particle is \( \frac{u^{2} \sin 2 \theta}{2 g}\left(1+\frac{1}{x}\right) \). Then the value of \( x \) is
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