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A \( \triangle A B C \) with sides \( A B=4 \mathrm{~cm}, B C=5 \mathrm{~cm} \) and \( C A=7 \mathrm{~cm} \) is given. To, construct a triangle whose sides are \( \frac{5}{7} \) times of the corresponding sides of the given triangle, first draw a ray \( B X \) such that \( \angle C B X \) is an acute angle and \( X \) lies on the opposite side
of \( A \) with respect to \( B C \). Then, locate points \( B_{1}, B_{2}, B_{3}, \ldots \) on \( B X \) at equal distances. What is the next step to join?
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