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An alloy of \( \mathrm{Pb}-\mathrm{Ag} \) weighing \( 1.08 \mathrm{~g} \) was dissolved in dilute \( \mathrm{HNO}_{3} \) and the volume made to \( 100 \mathrm{~mL} \). A silver electrode was dipped in the solution and the emf of the cell set-up as \( \mathrm{Pt}(\mathrm{s}), \mathrm{H}_{2}(\mathrm{~g})\left|\mathrm{H}^{+}(\mathrm{1M}) \| \mathrm{Ag}^{+}(\mathrm{aq})\right| \mathrm{Ag}(\mathrm{s}) \) was \( 0.62 \mathrm{~V} \). If \( E_{\text {cell }}^{o} \) is \( 0.80 \mathrm{~V} \), what is the percentage of \( \mathrm{Ag} \) in the alloy?
(At \( 25^{\circ} \mathrm{C}, R T / F=0.06 \) )
(A) 25
(B) \( 2.50 \)
(C) 10
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