An alternating voltage is given by: \( e=e_{1} \sin \omega t+e_{2} \cos \omega t \). Then the ro...
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0An alternating voltage is given by: \( e=e_{1} \sin \omega t+e_{2} \cos \omega t \). Then the root mean square value of voltage is given by
(a) \( \sqrt{e_{1}^{2}+e_{2}^{2}} \)
(b) \( \sqrt{e_{1} e_{2}} \)
(c) \( \sqrt{\frac{e_{1} e_{2}}{2}} \)
(d) \( \sqrt{\frac{e_{1}^{2}+e_{2}^{2}}{2}} \)
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