Capacitance of a parallel plate capacitor becomes \( 4 / 3 \) times its original value if a diel...
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Capacitance of a parallel plate capacitor becomes \( 4 / 3 \) times its original value if a dielectric slab of thickness \( \ell=d / 2 \) is inserted between the plates \( (d \) is the separation . between the plates). The dielectric constant of the slab is
(A) 8
(B) 4
(C) 6
(D) 2
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