Compound \(A\) reacts with \(NH _4 Cl\) and forms a compound B. Compound B reacts with \(H _2 O\....
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Compound \(A\) reacts with \(NH _4 Cl\) and forms a compound B. Compound B reacts with \(H _2 O\) and excess of \(CO _2\) to form compound \(C\) which on passing through or reaction with saturated \(NaCl\) solution forms sodium hydrogen carbonate. Compound A. B and C, are respectively. š²PW App Link - https://bit.ly/YTAI_PWAP šPW Website - https://www.pw.live