Comprehension- There are \( \mathrm{n} \) students in a class and the probability that exactly \...

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Comprehension-
There are \( \mathrm{n} \) students in a class and the probability that exactly \( k \) out of \( n \) pass the examination is directly proportional to \( k^{2}(0 \leq k \leq n) \). Then,
If the selected student has been found to pass the examination then the probability that he is the only student to have passed the examination, is
(a) \( \frac{1}{n(n+1)^{2}} \)
(b) \( \frac{1}{(n+1)} \)
(c) \( \frac{2}{n(n+1)^{2}} \)
(d) \( \frac{4}{[n(n+1)]^{2}} \)
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