Consider the following frequency distribution: \begin{tabular}{lllllll} \( X \) & 2 & 3 & 4 & 5 ....

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Consider the following frequency distribution:
\begin{tabular}{lllllll}
\( X \) & 2 & 3 & 4 & 5 & 6 & 7 \\
\( f \) & 4 & 9 & 16 & 14 & 11 & 6
\end{tabular}
\( \mathrm{P} \)
The standard deviation of the given data is
(1) 1.38
(2) 1.42
(3) 1.45
(4) 1.60



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