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Consider the situation shown. The switch \( \mathrm{S} \) is open for a long time and then closed. Then :
\( \mathrm{P} \)
\begin{tabular}{|l|l|l|l|}
\hline & Column I & & Column II \\
\hline (A) & \begin{tabular}{l}
Charge flown \\
through battery \\
when S is closed
\end{tabular} & (p) & \( \frac{C E^{2}}{2} \) \\
\hline (B) & \begin{tabular}{l}
Work done by \\
battery
\end{tabular} & (q) & \( \frac{C E}{2} \) \\
\hline (C) & \begin{tabular}{l}
Change in energy \\
stored in capacitor
\end{tabular} & (r) & \( \frac{C E^{2}}{4} \) \\
\hline (D) & \begin{tabular}{l}
Heat developed in \\
the system
\end{tabular} & (s) & \( \frac{C E^{2}}{8} \) \\
\hline & & (t) & \( \frac{C E}{4} \) \\
\hline
\end{tabular}
\begin{tabular}{lllll}
& A & B & C & D \\
(1) & \( \mathrm{q} \) & \( \mathrm{p} \) & \( \mathrm{r} \) & \( \mathrm{r} \) \\
(2) & \( \mathrm{s} \) & \( \mathrm{p} \) & \( \mathrm{r} \) & \( \mathrm{q} \) \\
(3) & \( \mathrm{r} \) & \( \mathrm{s} \) & \( \mathrm{q} \) & \( \mathrm{p} \) \\
(4) & \( \mathrm{p} \) & \( \mathrm{s} \) & \( \mathrm{r} \) & \( \mathrm{q} \)
\end{tabular}


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