Derivative as slope of a tangent line | Taking derivatives | Differential Calculus | Khan Academy

Channel:
Subscribers:
8,980,000
Published on ● Video Link: https://www.youtube.com/watch?v=ANyVpMS3HL4



Duration: 15:43
1,720,941 views
5,075


Courses on Khan Academy are always 100% free. Start practicing—and saving your progress—now: https://www.khanacademy.org/math/ap-calculus-ab/ab-differentiation-1-new/ab-2-2/v/calculus-derivatives-1-new-hd-version

Understanding that the derivative is just the slope of a curve at a point (or the slope of the tangent line)

Practice this yourself on Khan Academy right now: https://www.khanacademy.org/e/skill-check--tangent-lines?utm_source=YTdescription&utm_medium=YTdescription&utm_campaign=YTdescription

Watch the next lesson: https://www.khanacademy.org/math/differential-calculus/taking-derivatives/derivative_intro/v/tangent-slope-as-limiting-value-of-secant-slope-example-1?utm_source=YT&utm_medium=Desc&utm_campaign=DifferentialCalculus

Missed the previous lesson?
https://www.khanacademy.org/math/differential-calculus/taking-derivatives/secant-line-slope-tangent/v/approximating-equation-of-tangent-line-word-problem-1?utm_source=YT&utm_medium=Desc&utm_campaign=DifferentialCalculus

Differential calculus on Khan Academy: Limit introduction, squeeze theorem, and epsilon-delta definition of limits.

About Khan Academy: Khan Academy is a nonprofit with a mission to provide a free, world-class education for anyone, anywhere. We believe learners of all ages should have unlimited access to free educational content they can master at their own pace. We use intelligent software, deep data analytics and intuitive user interfaces to help students and teachers around the world. Our resources cover preschool through early college education, including math, biology, chemistry, physics, economics, finance, history, grammar and more. We offer free personalized SAT test prep in partnership with the test developer, the College Board. Khan Academy has been translated into dozens of languages, and 100 million people use our platform worldwide every year. For more information, visit www.khanacademy.org, join us on Facebook or follow us on Twitter at @khanacademy. And remember, you can learn anything.

For free. For everyone. Forever. #YouCanLearnAnything

Subscribe to KhanAcademy’s Differential Calculus channel:
https://www.youtube.com/channel/UCNLzjGl1HBdZrHXo4Vae3iA?sub_confirmation=1
Subscribe to KhanAcademy: https://www.youtube.com/subscription_center?add_user=khanacademy




Other Videos By Khan Academy


2009-11-03Determinant when row is added | Matrix transformations | Linear Algebra | Khan Academy
2009-11-03(correction) scalar multiplication of row | Matrix transformations | Linear Algebra | Khan Academy
2009-11-03Determinant when row multiplied by scalar | Matrix transformations | Linear Algebra | Khan Academy
2009-11-02Scientific notation examples | Pre-Algebra | Khan Academy
2009-11-02Rule of Sarrus of determinants | Matrix transformations | Linear Algebra | Khan Academy
2009-11-02Determinants along other rows/cols | Matrix transformations | Linear Algebra | Khan Academy
2009-11-02n x n determinant | Matrix transformations | Linear Algebra | Khan Academy
2009-11-023 x 3 determinant | Matrix transformations | Linear Algebra | Khan Academy
2009-11-02Introduction to scientific notation | Pre-Algebra | Khan Academy
2009-11-02Formula for 2x2 inverse | Matrix transformations | Linear Algebra | Khan Academy
2009-11-02Derivative as slope of a tangent line | Taking derivatives | Differential Calculus | Khan Academy
2009-11-02The derivative of f(x)=x^2 for any x | Taking derivatives | Differential Calculus | Khan Academy
2009-11-02Calculating slope of tangent line using derivative definition | Differential Calculus | Khan Academy
2009-10-31Example of finding matrix inverse | Matrix transformations | Linear Algebra | Khan Academy
2009-10-31Deriving a method for determining inverses | Matrix transformations | Linear Algebra | Khan Academy
2009-10-30Showing that inverses are linear | Matrix transformations | Linear Algebra | Khan Academy
2009-10-30Simplifying conditions for invertibility | Matrix transformations | Linear Algebra | Khan Academy
2009-10-30Matrix condition for one-to-one trans | Matrix transformations | Linear Algebra | Khan Academy
2009-10-30Exploring the solution set of Ax = b | Matrix transformations | Linear Algebra | Khan Academy
2009-10-30Simple Analysis of Cost per Job Saved from Stimulus
2009-10-29Determining whether a transformation is onto | Linear Algebra | Khan Academy