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For the reaction given below, the rate expression is given as :
\[
\mathrm{RX}+\mathrm{OH}^{-} \longrightarrow \mathrm{ROH}+X^{-}
\]
Rate \( =4.7 \times 10^{-5}[R X]\left[\mathrm{OH}^{-}\right]+0.24 \times 10^{-5}[R X] \)
What percentage of \( R X \) react by the \( S_{N^{2}} \) mechanism when
\[
\left[\mathrm{OH}^{-}\right]=0.001 M
\]
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