Duration: 4:19

123 views

0

From a solid sphere of mass \( M \) and radius \( R \), a spherical portion of radius \( \frac{R}{2} \) is removed, as shown in the figure. Taking gravitational potential \( V=0 \) at \( r=\infty \), the potential at the centre of the cavity thus formed is \( (G= \) gravitational constant)
(a) \( \frac{-2 G M}{3 R} \)
(b) \( \frac{-2 G M}{R} \)
(c) \( \frac{-G M}{2 R} \)
(d) \( \frac{-G M}{R} \)
\( \mathrm{P} \)
W
📲PW App Link - https://bit.ly/YTAI_PWAP
🌐PW Website - https://www.pw.live