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Given radius of Earth ' \( R \) ' and length of a day ' \( T \) ' the height of a geostationary satellite is [G-Gravitational Constant, M-Mass of Earth]
[MP PMT 2002]
(a) \( \left(\frac{4 \pi^{2} G M}{T^{2}}\right)^{1 / 3} \)
(b) \( \left(\frac{4 \pi G M}{R^{2}}\right)^{1 / 3}-R \)
(c) \( \left(\frac{G M T^{2}}{4 \pi^{2}}\right)^{1 / 3}-R \)
(d) \( \left(\frac{G M T^{2}}{4 \pi^{2}}\right)^{1 / 3}+R \)
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