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Ground state configuration of element having atomic number \( =24 \) is \( 3 d^{5} 4 s^{1} \). This is because
(a) the energy of \( 3 d \) and \( 4 s \)-orbitals is very low
(b) \( 3 d \) and \( 4 s \)-orbitals are of comparable energy
(c) Energy of \( 3 d \)-orbital is lower than the energy of \( 4 s \)-orbital
(d) Energy gap between third and fourth shell is very small
\( \mathrm{P} \)
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