If \( \cot ^{-1} 7+\cot ^{-1} 8+\cot ^{-1} 18=\cot ^{-1} k \), then...

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If \( \cot ^{-1} 7+\cot ^{-1} 8+\cot ^{-1} 18=\cot ^{-1} k \), then \( k \) is:
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