If \( e^{x}=\frac{\sqrt{1+t}-\sqrt{1-t}}{\sqrt{1+t}+\sqrt{1-t}} \) and \( \tan \frac{y}{2}=\sqrt...

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If \( e^{x}=\frac{\sqrt{1+t}-\sqrt{1-t}}{\sqrt{1+t}+\sqrt{1-t}} \) and \( \tan \frac{y}{2}=\sqrt{\frac{1-t}{1+t}} \), then \( \frac{d y}{d x} \) at \( t=\frac{1}{2} \) is
(A) \( -\frac{1}{2} \)
(B) \( \frac{1}{2} \)
(C) none of these
(D) undefined
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